(x^2-x+1)(x^2+x+1)=

Solution for (x^2-x+1)(x^2+x+1)= equation:

Simplifying
(x2 + -1x + 1)(x2 + x + 1) = 0

Reorder the terms:
(1 + -1x + x2)(x2 + x + 1) = 0

Reorder the terms:
(1 + -1x + x2)(1 + x + x2) = 0

Multiply (1 + -1x + x2) * (1 + x + x2)
(1(1 + x + x2) + -1x * (1 + x + x2) + x2(1 + x + x2)) = 0
((1 * 1 + x * 1 + x2 * 1) + -1x * (1 + x + x2) + x2(1 + x + x2)) = 0
((1 + 1x + 1x2) + -1x * (1 + x + x2) + x2(1 + x + x2)) = 0
(1 + 1x + 1x2 + (1 * -1x + x * -1x + x2 * -1x) + x2(1 + x + x2)) = 0
(1 + 1x + 1x2 + (-1x + -1x2 + -1x3) + x2(1 + x + x2)) = 0
(1 + 1x + 1x2 + -1x + -1x2 + -1x3 + (1 * x2 + x * x2 + x2 * x2)) = 0
(1 + 1x + 1x2 + -1x + -1x2 + -1x3 + (1x2 + x3 + x4)) = 0

Reorder the terms:
(1 + 1x + -1x + 1x2 + -1x2 + 1x2 + -1x3 + x3 + x4) = 0

Combine like terms: 1x + -1x = 0
(1 + 0 + 1x2 + -1x2 + 1x2 + -1x3 + x3 + x4) = 0
(1 + 1x2 + -1x2 + 1x2 + -1x3 + x3 + x4) = 0

Combine like terms: 1x2 + -1x2 = 0
(1 + 0 + 1x2 + -1x3 + x3 + x4) = 0
(1 + 1x2 + -1x3 + x3 + x4) = 0

Combine like terms: -1x3 + x3 = 0
(1 + 1x2 + 0 + x4) = 0
(1 + 1x2 + x4) = 0

Solving
1 + 1x2 + x4 = 0

Solving for variable 'x'.

Begin completing the square.

Move the constant term to the right:

Add '-1' to each side of the equation.
1 + 1x2 + -1 + x4 = 0 + -1

Reorder the terms:
1 + -1 + 1x2 + x4 = 0 + -1

Combine like terms: 1 + -1 = 0
0 + 1x2 + x4 = 0 + -1
1x2 + x4 = 0 + -1

Combine like terms: 0 + -1 = -1
1x2 + x4 = -1

The x term is 1x2.  Take half its coefficient (0.5).
Square it (0.25) and add it to both sides.

Add '0.25' to each side of the equation.
x2 + 0.25 + x4 = -1 + 0.25

Reorder the terms:
0.25 + x2 + x4 = -1 + 0.25

Combine like terms: -1 + 0.25 = -0.75
0.25 + x2 + x4 = -0.75

Factor a perfect square on the left side:
(x2 + 0.5)(x2 + 0.5) = -0.75

Can't calculate square root of the right side.

The solution to this equation could not be determined.